Triphenylphosphine → alpha-Methylcinnamic alcohol
반응식
C1(P(C2C=CC=CC=2)C2C=CC=CC=2)C=CC=CC=1.[OH-].[Na+].[CH3:22]/[C:23](/[CH:31]=[O:32])=[CH:24]/[C:25]1[CH:30]=[CH:29][CH:28]=[CH:27][CH:26]=1.[H][H]>>[CH3:22]/[C:23](/[CH2:31][OH:32])=[CH:24]\[C:25]1[CH:30]=[CH:29][CH:28]=[CH:27][CH:26]=1참가 물질
5
실험 절차
Into a stainless steel autoclave equipped with a glass inner tube, Cu(NO3)(PPh3)2 (11.7 mg, 0.018 mmol) and triphenylphosphine (28.3 mg, 0.108 mmol) were introduced. The inside of the autoclave was then replaced with nitrogen. To the autoclave, an ethanolic solution of sodium hydroxide (0.03 M) (6.0 mL, 0.18 mmol) and α-methyl cinnamic aldehyde (1.26 mL, 9 mmol) were added, and stirring was performed at a hydrogen pressure of 5 MPa at 50° C. for 16 hours. The hydrogen was released with great care, and the conversion was analyzed by GC (>99%). The contents were concentrated, and then purified by silica gel chromatography. Thus, 1.25 g of the α-methyl cinnamic alcohol was obtained (yield: 94%).