C(=O)([O-])[O-].C[C:6]1([PH3+:12])[CH:11]=[CH:10][CH:9]=[CH:8][CH2:7]1.C[C:14]1([PH3+:20])C=CC=CC1.[Cl:21]([O-:25])(=[O:24])(=[O:23])=[O:22]>O>[C:6]1([PH2:12])[CH:11]=[CH:10][CH:9]=[CH:8][CH:7]=1.[Cl:21]([O-:25])(=[O:24])(=[O:23])=[O:22].[CH3:14][PH3+:20]By following the same procedure as the 2nd step of Example 12 except that 10.0 g of 1-methylphenylphosphanium carbonate, 6.9 g of 60% perchlorate, and 10.0 g of water were used, 10.9 g (94.8% of the theoretical yield, yield of 67.6% to 1-phenylphosphane) of methylphosphanium perchlorate was obtained.
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