Iodoethane → N-Ethylphenothiazine
반응식
[CH:1]1[C:14]2[NH:13][C:12]3[C:7](=[CH:8][CH:9]=[CH:10][CH:11]=3)[S:6][C:5]=2[CH:4]=[CH:3][CH:2]=1.I[CH2:16][CH3:17].[OH-].[K+]>S([O-])(O)(=O)=O.C([N+](CCCC)(CCCC)CCCC)CCC.C1(C)C=CC=CC=1>[CH2:16]([N:13]1[C:14]2[CH:1]=[CH:2][CH:3]=[CH:4][C:5]=2[S:6][C:7]2[C:12]1=[CH:11][CH:10]=[CH:9][CH:8]=2)[CH3:17]참가 물질
6
실험 절차
A mixture of 10 g (0.05 mol) of phenothiazine, 11.7 g (0.075 mol) of iodoethane, 4.2 g (0.075 mol) of potassium hydroxide and 0.25 g of tetra-n-butylammonium hydrogen sulfate in 200 ml of dry toluene was refluxed for 24 hours. After cooling, the reaction mixture was filtered, and the solvent was evaporated. The product was crystallized from methanol. The yield of 10-ethylphenothiazine (C14H13NS, FW=227.33) was 90%.
후처리
- temperaturewas refluxed for 24 hours
- temperatureAfter cooling
- filtrationthe reaction mixture was filtered
- customthe solvent was evaporated
- customThe product was crystallized from methanol
출처 및 근거
- ORD 기록
- ord-625c6e1d30dd4d0a9f0e4279bcd0f5ff
- 출처 데이터셋
- uspto-grants-2006_08
- 특허 번호
- US07083884B2
반응 노트
불러오는 중…