2,5-Dimethylphenol → HCID 57743410, compound

HRID 1095098Notes

Reaction equation

HRID 1095098 reaction equation
[Br:1][C:2]1[CH:3]=[CH:4][C:5](F)=[C:6]([CH:9]=1)[CH:7]=[O:8].[CH3:11][C:12]1[CH:17]=[CH:16][C:15]([CH3:18])=[CH:14][C:13]=1[OH:19].C([O-])([O-])=O.[K+].[K+]>CN(C)C(=O)C>[Br:1][C:2]1[CH:3]=[CH:4][C:5]([O:19][C:13]2[CH:14]=[C:15]([CH3:18])[CH:16]=[CH:17][C:12]=2[CH3:11])=[C:6]([CH:9]=1)[CH:7]=[O:8]

Participants

5

Reactant 3

HCID 72672,5-DimethylphenolHCID 11430Potassium CarbonateHCID 7363275-Bromo-2-fluorobenzaldehyde

Product 1

HCID 57743410HCID 57743410, compoundYield 98.3%

Reagents, catalysts & solvents 1

HCID 31374DimethylacetamideSolvent

Procedure

In a manner similar to the method described in Example 50a, 5-bromo-2-fluorobenzaldehyde (2.1 g, 10 mmol) (Alfa) was reacted with 2,5-dimethylphenol (1.4 g, 11 mmol) and K2CO3 in N,N-dimethylacetamide to give 5-bromo-2-(2,5-dimethyl-phenoxy)-benzaldehyde as an orange oil (Yield 3 g, 98%).

Sources & evidence

ORD record
ord-ff1a64f8599c412bb3e0af7a59fd3965
Source dataset
uspto-grants-2012_03
Patent number
US08134001B2

Reaction notes

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