Triphenylphosphine → HCID 59093854, compound

HRID 1167682Notes

Reaction equation

HRID 1167682 reaction equation
[O:1]=[C:2]1[NH:6][C:5](=[O:7])[C:4]2([CH2:12][CH2:11][N:10]([C:13]([O:15][C:16]([CH3:19])([CH3:18])[CH3:17])=[O:14])[CH2:9][CH2:8]2)[NH:3]1.[CH3:20][O:21][C:22](=[O:46])[C@H:23]([CH2:44]O)[NH:24][C:25]([C:38]1[CH:43]=[CH:42][CH:41]=[CH:40][CH:39]=1)([C:32]1[CH:37]=[CH:36][CH:35]=[CH:34][CH:33]=1)[C:26]1[CH:31]=[CH:30][CH:29]=[CH:28][CH:27]=1.C1(P(C2C=CC=CC=2)C2C=CC=CC=2)C=CC=CC=1.N(C(OCC)=O)=NC(OCC)=O>C1COCC1>[CH3:20][O:21][C:22]([C@@H:23]([NH:24][C:25]([C:38]1[CH:43]=[CH:42][CH:41]=[CH:40][CH:39]=1)([C:26]1[CH:27]=[CH:28][CH:29]=[CH:30][CH:31]=1)[C:32]1[CH:37]=[CH:36][CH:35]=[CH:34][CH:33]=1)[CH2:44][N:6]1[C:5](=[O:7])[C:4]2([CH2:8][CH2:9][N:10]([C:13]([O:15][C:16]([CH3:19])([CH3:18])[CH3:17])=[O:14])[CH2:11][CH2:12]2)[NH:3][C:2]1=[O:1])=[O:46]

Participants

6

Procedure

A solution of 3.6 g (13.37 mmol) of (34.2) in 15 ml of absolute THF is added to a solution of 3.72 g (10.3 mmol) of (34.3) and 3.5 g (13.34 mmol) of triphenylphosphine in 20 ml of absolute THF. 2.11 ml (13.37 mmol) of diethyl azodicarboxylate (DEAD) are added to this solution and the reaction mixture is stirred at room temperature until the reaction has come to an end. The solvent is removed in vacuo and the residue is chromatographed through silica gel using heptane/ethyl acetate. 6 g (95%) of (34.4) are obtained after concentrating the product fractions.

Workup

  1. customThe solvent is removed in vacuo
  2. customthe residue is chromatographed through silica gel

Sources & evidence

ORD record
ord-5ea45d0e79e44886a907e357ec190980
Source dataset
uspto-grants-2003_09
Patent number
US06620820B2

Reaction notes

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