Iodine → 4-hydroxy-3-methoxy-2-nitrobenzonitrile
Reaction equation
[OH:1][C:2]1[CH:9]=[CH:8][C:5]([CH:6]=O)=[C:4]([N+:10]([O-:12])=[O:11])[C:3]=1[O:13][CH3:14].[OH-].[NH4+:16].II>C1COCC1>[OH:1][C:2]1[CH:9]=[CH:8][C:5]([C:6]#[N:16])=[C:4]([N+:10]([O-:12])=[O:11])[C:3]=1[O:13][CH3:14]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
4-Hydroxy-3-methoxy-2-nitrobenzaldehyde (200 g, 1.01 mol) was dissolved in THF (2.5 L) and then ammonium hydroxide (2.5 L) was added followed by iodine (464 g, 1.8 mol).
Sources & evidence
- ORD record
- ord-a638210d2e6c4c1296028b718b48653d
- Source dataset
- uspto-grants-2013_06
- Patent number
- US08466283B2
Reaction notes
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