Potassium Iodide → HCID 14422900, compound

HRID 1382402Notes

Reaction equation

HRID 1382402 reaction equation
[Cl:1][CH2:2][CH2:3][CH:4]([OH:15])[CH2:5][O:6][C:7]1[CH:12]=[CH:11][C:10]([C:13]#[N:14])=[CH:9][CH:8]=1.[C:16]1([N:22]2[CH2:27][CH2:26][NH:25][CH2:24][CH2:23]2)[CH:21]=[CH:20][CH:19]=[CH:18][CH:17]=1.C(=O)([O-])[O-].[Na+].[Na+].[I-].[K+]>Cl.C(O)CCC>[ClH:1].[ClH:1].[C:13]([C:10]1[CH:11]=[CH:12][C:7]([O:6][CH2:5][CH:4]([OH:15])[CH2:3][CH2:2][N:25]2[CH2:26][CH2:27][N:22]([C:16]3[CH:21]=[CH:20][CH:19]=[CH:18][CH:17]=3)[CH2:23][CH2:24]2)=[CH:8][CH:9]=1)#[N:14]

Participants

7

Reactant 4

HCID 4875Potassium IodideHCID 70961-PhenylpiperazineHCID 10340Sodium CarbonateHCID 14422834HCID 14422834, compound

Product 1

HCID 14422900HCID 14422900, compound

Reagents, catalysts & solvents 2

HCID 2631-ButanolSolventHCID 313Hydrochloric AcidSolvent

Procedure

This compound was prepared according to the procedure of Example 97. A mixture of 6.8 g (0.03 mole) of 4-chloro-1-(4-cyanophenoxy)-2-butanol, 4.9 g (0.03 mole) of 1-phenylpiperazine, 16.0 g (0.15 mole) of anhydrous sodium carbonate and 0.3 g (0.002 mole) of potassium iodide in a total volume of 200 ml of 1-butanol gave an oil as residue. The hydrochloric acid salt was formed in ethereal hydrogen chloride and the collected solid was recrystallized from methanolethyl ether to give 3.7 g (35%) of white solid, m.p. 195°-198° C.

Workup

  1. customThis compound was prepared
  2. customgave an oil as residue

Sources & evidence

ORD record
ord-09f7a6a1c6714fc1b66a22799758718e
Source dataset
uspto-grants-1989_02
Patent number
US04806555

Reaction notes

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