Potassium Iodide → Hydrochloric Acid

HRID 1382409Notes

Reaction equation

HRID 1382409 reaction equation
[Cl:1][CH2:2][CH2:3][CH:4]([OH:16])[CH2:5][O:6][C:7]1[CH:12]=[CH:11][C:10]([C:13](=[O:15])[CH3:14])=[CH:9][CH:8]=1.[C:17]1([N:23]2[CH2:28][CH2:27][NH:26][CH2:25][CH2:24]2)[CH:22]=[CH:21][CH:20]=[CH:19][CH:18]=1.C(=O)([O-])[O-].[Na+].[Na+].[I-].[K+]>CC(O)C.C(O)CCC>[ClH:1].[ClH:1].[C:13]([C:10]1[CH:11]=[CH:12][C:7]([O:6][CH2:5][CH:4]([OH:16])[CH2:3][CH2:2][N:26]2[CH2:27][CH2:28][N:23]([C:17]3[CH:22]=[CH:21][CH:20]=[CH:19][CH:18]=3)[CH2:24][CH2:25]2)=[CH:8][CH:9]=1)(=[O:15])[CH3:14].[ClH:1]

Participants

8

Reactant 4

HCID 4875Potassium IodideHCID 70961-PhenylpiperazineHCID 10340Sodium CarbonateHCID 13120356HCID 13120356, compound

Product 2

HCID 313Hydrochloric AcidHCID 14422878HCID 14422878, compound

Reagents, catalysts & solvents 2

HCID 2631-ButanolSolventHCID 3776IsopropanolSolvent

Procedure

This compound was prepared according to the procedure of Example 97. A mixture of 7.3 g (0.03 mole) of 1-[4-(4-chloro-2-hydroxybutoxy)phenyl]ethanone, 5.0 g (0.03 mole) of 1-phenylpiperazine, 16.0 g (0.15 mole) of anhydrous sodium carbonate and 0.3 g (0.002 mole) of potassium iodide in a total volume of 200 ml of 1-butanol gave a brown oil as residue. The hydrochloric acid salt was formed in 2-propanol saturated with hydrogen chloride, and the collected solid was recrystallized from 95% ethanol to give 5.6 g (42%) of pale yellow solid, m.p. 203°-208° C.

Workup

  1. customThis compound was prepared
  2. customgave a brown oil as residue

Sources & evidence

ORD record
ord-ee83cc98c485422188a6733b3929d66e
Source dataset
uspto-grants-1989_02
Patent number
US04806555

Reaction notes

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