Potassium Iodide → Hydrochloric Acid

HRID 1382414Notes

Reaction equation

HRID 1382414 reaction equation
[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([N:8]2[CH2:13][CH2:12][NH:11][CH2:10][CH2:9]2)=[CH:4][CH:3]=1.[Cl:14][CH2:15][CH2:16][CH:17]([OH:27])[CH2:18][O:19][C:20]1[CH:25]=[CH:24][C:23]([Cl:26])=[CH:22][CH:21]=1.C(=O)([O-])[O-].[Na+].[Na+].[I-].[K+]>CC(O)C.C(O)CCC>[ClH:1].[ClH:14].[Cl:26][C:23]1[CH:24]=[CH:25][C:20]([O:19][CH2:18][CH:17]([OH:27])[CH2:16][CH2:15][N:11]2[CH2:12][CH2:13][N:8]([C:5]3[CH:4]=[CH:3][C:2]([Cl:1])=[CH:7][CH:6]=3)[CH2:9][CH2:10]2)=[CH:21][CH:22]=1.[ClH:1]

Participants

8

Reactant 4

HCID 4875Potassium IodideHCID 10340Sodium CarbonateHCID 974781-(4-Chlorophenyl)piperazineHCID 131203494-Chloro-1-(4-chlorophenoxy)-2-butanol

Product 2

HCID 313Hydrochloric AcidHCID 14422865HCID 14422865, compound

Reagents, catalysts & solvents 2

HCID 2631-ButanolSolventHCID 3776IsopropanolSolvent

Procedure

This compound was prepared according to the procedure of Example 97. A mixture of 3.2 g (0.016 mole) of 1-(4-chlorophenyl)piperazine, 3.8 g (0.016 mole) of 4-chloro-1-(4-chlorophenoxy)-2-butanol, 8.3 g (0.078 mole) of anhydrous sodium carbonate and 0.1 g of potassium iodide in a total volume of 200 ml of 1-butanol gave a golden oil as residue. The hydrochloride was formed in 2-propanol saturated with hydrogen chloride and the collected solid was recrystallized from methol-water-ethyl ether to give 3.6 g (47%) of white solid, m.p. 195°-200° C.

Workup

  1. customThis compound was prepared
  2. customgave a golden oil as residue

Sources & evidence

ORD record
ord-fda09097e9af4840ac19806f89bd757c
Source dataset
uspto-grants-1989_02
Patent number
US04806555

Reaction notes

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