Hexachloroethane → HCID 86686971, compound

HRID 1402107Notes

Reaction equation

HRID 1402107 reaction equation
[F:1][C:2]1[CH:3]=[CH:4][C:5]([NH:8][NH:9][C:10](=O)[CH2:11][N:12]2[CH2:17][CH2:16][N:15]([CH3:18])[CH2:14][CH2:13]2)=[N:6][CH:7]=1.C1(P(C2C=CC=CC=2)C2C=CC=CC=2)C=CC=CC=1.C(N(CC)CC)C.ClC(Cl)(Cl)C(Cl)(Cl)Cl>C1COCC1>[F:1][C:2]1[CH:3]=[CH:4][C:5]2[N:6]([C:10]([CH2:11][N:12]3[CH2:17][CH2:16][N:15]([CH3:18])[CH2:14][CH2:13]3)=[N:9][N:8]=2)[CH:7]=1

Participants

6

Reactant 4

HCID 6214HexachloroethaneHCID 8471TriethylamineHCID 11776TriphenylphosphineHCID 86686972HCID 86686972, compound

Product 1

HCID 86686971HCID 86686971, compoundYield 89%

Reagents, catalysts & solvents 1

HCID 8028TetrahydrofuranSolvent

Procedure

Intermediate 14a (570 mg, 2.13 mmol) was dissolved in THF (20.0 mL) and cooled in an ice/water bath. Triphenylphosphine (1.12 g, 4.27 mmol) was added followed by triethylamine (1.19 mL, 8.54 mmol) and hexachloroethane (1.01 g, 4.27 mmol). The reaction was stirred for 18 h. The mixture was loaded onto an SCX-2 cartridge, washing with MeOH and eluting with 2M NH3 in MeOH. The residue was purified by FCC, using 0-10% [2M NH3 in MeOH] in DCM, to give the title compound (470 mg, 1.89 mmol, 89%). LCMS (Method 1): Rt 0.36 min, m/z 250 [MH+].

Workup

  1. temperaturecooled in an ice/water bath
  2. washwashing with MeOH
  3. washeluting with 2M NH3 in MeOH
  4. customThe residue was purified by FCC

Sources & evidence

ORD record
ord-df7ee778a86444e185c8bb491ead1a1e
Source dataset
uspto-grants-2014_12
Patent number
US08907094B2

Reaction notes

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