Hexachloroethane → HCID 86687117, compound

HRID 1402276Notes

Reaction equation

HRID 1402276 reaction equation
[F:1][C:2]1[CH:3]=[CH:4][C:5]([NH:8][NH:9][C:10]([C@:12]2([CH2:18][O:19][Si:20]([CH:27]([CH3:29])[CH3:28])([CH:24]([CH3:26])[CH3:25])[CH:21]([CH3:23])[CH3:22])[CH2:16][CH2:15][CH2:14][N:13]2[CH3:17])=O)=[N:6][CH:7]=1.C1C=CC(P(C2C=CC=CC=2)C2C=CC=CC=2)=CC=1.CCN(CC)CC.ClC(Cl)(Cl)C(Cl)(Cl)Cl>C1COCC1.C(Cl)Cl>[F:1][C:2]1[CH:3]=[CH:4][C:5]2[N:6]([C:10]([C@:12]3([CH2:18][O:19][Si:20]([CH:27]([CH3:29])[CH3:28])([CH:24]([CH3:26])[CH3:25])[CH:21]([CH3:23])[CH3:22])[CH2:16][CH2:15][CH2:14][N:13]3[CH3:17])=[N:9][N:8]=2)[CH:7]=1

Participants

7

Reactant 4

HCID 6214HexachloroethaneHCID 8471TriethylamineHCID 11776TriphenylphosphineHCID 86687118HCID 86687118, compound

Product 1

HCID 86687117HCID 86687117, compoundYield 41.4%

Reagents, catalysts & solvents 2

HCID 6344DichloromethaneSolventHCID 8028TetrahydrofuranSolvent

Procedure

To a solution of Intermediate 85h (1.37 g, 2.08 mmol), Ph3P (1.09 g, 4.16 mmol) and Et3N (840 mg, 8.32 mmol) in THF (60 mL) was added hexachloroethane (980 mg, 4.16 mmol) and the mixture stirred at RT for 20 h. The mixture was diluted with DCM, washed with 10% aq. K2CO3 solution, brine, dried (MgSO4) and concentrated in vacuo. The residue was purified by FCC, using 0-100% EtOAc in cyclohexane, to give the title compound as a clear oil (350 mg, 41%). LCMS (Method 4): Rt 3.07 min, m/z 407 [MH+].

Workup

  1. washwashed with 10% aq. K2CO3 solution, brine
  2. dry with materialdried (MgSO4)
  3. concentrationconcentrated in vacuo
  4. customThe residue was purified by FCC

Sources & evidence

ORD record
ord-3b2ebf23df534fcc90c1e30b06864f21
Source dataset
uspto-grants-2014_12
Patent number
US08907094B2

Reaction notes

Loading…