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HRID1436608

反应详情

EQUATION

反应方程式

HRID 1436608 的结构方程式

REACTANTS

反应物

3
结构：Cl
HCID313

Hydrochloric Acid

ClH

结构：[Li+].[OH-]
HCID3939

Lithium hydroxide anhydrous

HLiO

结构：CCCN(C)c1cc(C(=O)OC)cc(N(C)S(C)(=O)=O)n1
HCID68815178

未命名化合物

PRODUCTS

生成物

1
结构：CCCN(C)c1cc(C(=O)O)cc(N(C)S(C)(=O)=O)n1
HCID68814989

未命名化合物

收率 85.6%

AUXILIARIES

试剂、催化剂与溶剂

1
结构：C1CCOC1
溶剂HCID8028

Tetrahydrofuran

C4H8O

PROCEDURE

实验过程

Dissolve 2-(methanesulfonyl-methylamino)-6-(methylpropylamino)-isonicotinic acid methyl ester (796 mg, 2.52 mmoles) in THF (35 mL) and add 1 N lithium hydroxide (12.6 mL). Stir at room temperature for 16 h, acidify with 5 N HCl (2.6 mL), and partition between diethyl ether and water. Wash the diethyl ether layer with saturated aqueous sodium chloride, dry (magnesium sulfate) and concentrate to give the title compound as a yellow solid (650 mg, 85%).

WORKUP

后处理

  1. custompartition between diethyl ether and water
  2. washWash the diethyl ether layer with saturated aqueous sodium chloride
  3. dry with materialdry (magnesium sulfate)
  4. concentrationconcentrate