Lithium Hydroxide → HCID 86604233, compound

HRID 1452705Notes

Reaction equation

HRID 1452705 reaction equation
[CH3:1][C:2]1[CH:27]=[C:26]([C:28]([OH:37])([C:33]([F:36])([F:35])[F:34])[C:29]([F:32])([F:31])[F:30])[CH:25]=[CH:24][C:3]=1[O:4][C@@H:5]([CH2:17][C:18]1[CH:23]=[CH:22][CH:21]=[CH:20][CH:19]=1)[CH2:6][O:7][C:8]1[CH:16]=[CH:15][C:11]([C:12]([OH:14])=[O:13])=[CH:10][CH:9]=1.[OH-].[Li+:39]>C1COCC1>[CH3:1][C:2]1[CH:27]=[C:26]([C:28]([OH:37])([C:29]([F:30])([F:31])[F:32])[C:33]([F:35])([F:36])[F:34])[CH:25]=[CH:24][C:3]=1[O:4][C@@H:5]([CH2:17][C:18]1[CH:23]=[CH:22][CH:21]=[CH:20][CH:19]=1)[CH2:6][O:7][C:8]1[CH:16]=[CH:15][C:11]([C:12]([O-:14])=[O:13])=[CH:10][CH:9]=1.[Li+:39]

Participants

4

Reactant 2

HCID 3939Lithium HydroxideHCID 11649415HCID 11649415, compound

Product 1

HCID 86604233HCID 86604233, compoundYield 98.2%

Reagents, catalysts & solvents 1

HCID 8028TetrahydrofuranSolvent

Procedure

20.2 mg (0.04 mmol) of 4-{(S)-2-[2-methyl-4-(2,2,2-trifluoro-1-hydroxy-1-trifluoromethyl-ethyl)-phenoxy]-3-phenyl-propoxy}-benzoic acid (example 36) in 3 mL of THF were treated with 1 mg (0.04 mmol) of lithium hydroxide. The solvent was evaporated to give 21 mg (quantitative) of lithium 4-{(S)-2-[2-methyl-4-(2,2,2-trifluoro-1-hydroxy-1-trifluoromethyl-ethyl)-phenoxy]-3-phenyl-propoxy}-benzoate as a light yellow oil, MS: 527 (M−H)−.

Workup

  1. customThe solvent was evaporated

Sources & evidence

ORD record
ord-2f16f15cc6a24d35b7453de46e3689da
Source dataset
uspto-grants-2009_01
Patent number
US07473705B2

Reaction notes

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