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HRID1462428

反应详情

EQUATION

反应方程式

HRID 1462428 的结构方程式

REACTANTS

反应物

3
结构：[H-].[Na+]
HCID24758

Sodium hydride

HNa

结构：COC(=O)CBr
HCID60984

Methyl bromoacetate

C3H5BrO2

结构：O=C(CNC(=O)c1ccc(Cl)cc1)c1ccsc1
HCID13105428

未命名化合物

PRODUCTS

生成物

1
结构：COC(=O)CC(NC(=O)c1ccc(Cl)cc1)C(=O)c1ccsc1
HCID13345231

未命名化合物

收率 64.3%

PROCEDURE

实验过程

23 g of N-(4-chlorobenzoyl)-N-[(3-thienylcarbonyl)methyl]amine, 6.1 g of 50% sodium hydride and 21.8 g of methyl bromoacetate are treated in the same manner as described in Preparation 1-(4). 18.6 g of methyl 3-(4-chlorobenzoylamino)-3-(3-thienylcarbonyl)propionate are thereby obtained.

WORKUP

后处理

  1. customas described in Preparation 1-(4)