Potassium Iodide → Hydrochloric Acid

HRID 1639092Notes

Reaction equation

HRID 1639092 reaction equation
[Cl:1][CH2:2][CH2:3][CH:4]([OH:14])[CH2:5][O:6][C:7]1[CH:12]=[CH:11][C:10]([F:13])=[CH:9][CH:8]=1.[N:15]1[CH:20]=[CH:19][CH:18]=[CH:17][C:16]=1[N:21]1[CH2:26][CH2:25][NH:24][CH2:23][CH2:22]1.C(=O)([O-])[O-].[Na+].[Na+].[I-].[K+]>CC(O)C.C(O)CCC>[ClH:1].[ClH:1].[F:13][C:10]1[CH:11]=[CH:12][C:7]([O:6][CH2:5][CH:4]([OH:14])[CH2:3][CH2:2][N:24]2[CH2:25][CH2:26][N:21]([C:16]3[CH:17]=[CH:18][CH:19]=[CH:20][N:15]=3)[CH2:22][CH2:23]2)=[CH:8][CH:9]=1.[ClH:1]

Participants

8

Reactant 4

HCID 4875Potassium IodideHCID 10340Sodium CarbonateHCID 944591-(2-Pyridyl)piperazineHCID 14422830HCID 14422830, compound

Product 2

HCID 313Hydrochloric AcidHCID 14422884HCID 14422884, compound

Reagents, catalysts & solvents 2

HCID 2631-ButanolSolventHCID 3776IsopropanolSolvent

Procedure

This compound was prepared according to the procedure of Example 25. A mixture of 6.6 g (0.03 mole) of 4-chloro-1-(4-fluorophenoxy)-2-butanol, 4.9 g (0.03 mole) of 1-(2-pyridyl)piperazine, 16.0 g (0.15 mole) of anhydrous sodium carbonate and 0.3 g of potassium iodide in a total volume of 200 ml of 1-butanol gave a golden oil as residue. The hydrochloride was formed in 2-propanol saturated with hydrogen chloride and the collected solid was recrystallized from methanol/water to give 9.0 g (72%) of white solid, m.p. >245° C.

Workup

  1. customThis compound was prepared
  2. customgave a golden oil as residue

Sources & evidence

ORD record
ord-84195d96bdf24fa0be38efe1b862b9b9
Source dataset
uspto-grants-1989_11
Patent number
US04882330

Reaction notes

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