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HRID1657327

反应详情

EQUATION

反应方程式

HRID 1657327 的结构方程式

REACTANTS

反应物

2
结构：CC(=O)O[C@H]1C(=O)[C@@]2(C)[C@H]([C@H](OC(=O)c3ccccc3)[C@]3(O)C[C@H](OC(=O)[C@H](O)[C@@H](NC(=O)c4ccccc4)c4ccccc4)C(C)=C1C3(C)C)[C@]1(OC(C)=O)CO[C@@H]1C[C@@H]2O
HCID36314

Paclitaxel

C47H51NO14

结构：CC(=O)O[C@@]12CO[C@@H]1C[C@H](O)[C@@]1(C)C(=O)[C@H](O)C3=C(C)[C@@H](OC(=O)[C@H](O)[C@@H](NC(=O)c4ccccc4)c4ccccc4)C[C@@](O)([C@@H](OC(=O)c4ccccc4)[C@H]21)C3(C)C
HCID155831

10-Deacetyltaxol

C45H49NO13

PRODUCTS

生成物

1
结构：CC(=O)O[C@@]12CO[C@@H]1C[C@H](O)[C@@]1(C)C(=O)[C@H](O)C3=C(C)[C@@H](O)C[C@@](O)([C@@H](OC(=O)c4ccccc4)[C@H]21)C3(C)C
HCID154272

10-Deacetylbaccatin III

C29H36O10

AUXILIARIES

试剂、催化剂与溶剂

1
结构：ClCCl
溶剂HCID6344

Dichloromethane

CH2Cl2

PROCEDURE

实验过程

In contrast, the same procedure as described in Example II was run on 10 grams of starting material having the same taxol and 10-deacetyltaxol percentages. The reaction solvent used was dichloromethane (as was used in the Magris, et al. procedure). The 10-deacetylbaccatin III yield was only 24%, 90 mg (a lower yield resulted from larger amounts of material) as analyzed by TLC. there as 69 mg of 10-deacetyltaxol remaining; 47% of the 10-deacetyltaxol was converted. Based on TLC analysis, the reaction in dichloromethane was run for one hundred twenty hours versus seventy-two hours.