Hydrogen Peroxide → Catechol

HRID 1678932Notes

Reaction equation

HRID 1678932 reaction equation
[C:1]1([OH:7])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.[OH:8]O>CC(C)CC(=O)C>[C:1]1([C:6](=[CH:5][CH:4]=[CH:3][CH:2]=1)[OH:8])[OH:7].[C:1]1([CH:6]=[CH:5][C:4]([OH:8])=[CH:3][CH:2]=1)[OH:7]

Participants

5

Reactant 2

HCID 784Hydrogen PeroxideHCID 996Phenol

Product 2

HCID 289CatecholHCID 785Hydroquinone

Reagents, catalysts & solvents 1

HCID 7909Methyl Isobutyl KetoneSolvent

Procedure

To a mixture of 10 g. (106 m. moles) of phenol, 0.820 g. (8.20 m. moles) of 4-methyl-2-pentanone and 0.300 g. (5.29 m. moles) of 60 percent hydrogen peroxide was added the catalyst indicated in Table 4, and the reaction was effected at 100° C. for 30 minutes in the same manner as in Example 1. The reaction in Example 26 was effected at 160° C. for 1 hour. Yields of catechol and hydroquinone are shown in Table 4.

Workup

  1. additionTo a mixture of 10 g
  2. customThe reaction in Example 26
  3. waitwas effected at 160° C. for 1 hour

Sources & evidence

ORD record
ord-d6d4e22a8c714089824c36089de40b5a
Source dataset
uspto-grants-1978_03
Patent number
US04078006

Reaction notes

Loading…