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HRID1815062

反应详情

EQUATION

反应方程式

HRID 1815062 的结构方程式

REACTANTS

反应物

2
结构：Cl
HCID313

Hydrochloric Acid

ClH

结构：CC(C)(C)OC(=O)N1CCC(Oc2ccccn2)CC1
HCID21906039

tert-Butyl 4-[(pyridin-2-yl)oxy]piperidine-1-carboxylate

C15H22N2O3

PRODUCTS

生成物

1
结构：Cl.Cl.c1ccc(OC2CCNCC2)nc1
HCID14674154

Pyridine, 2-(4-piperidinyloxy)-, hydrochloride (1:2)

C10H16Cl2N2O

收率 90%

AUXILIARIES

试剂、催化剂与溶剂

1
结构：CCOC(C)=O
溶剂HCID8857

Ethyl acetate

C4H8O2

PROCEDURE

实验过程

1-t-Butoxycarbonyl-4-(2-pyridoxy)piperidine (6.5 g) was treated with a solution of hydrogen chloride in ethyl acetate (110 mL) for 7 h, and the mixture evaporated to give 4-(2-pyridoxy)piperidine dihydrochloride (7.4 g, 90%).

WORKUP

后处理

  1. customthe mixture evaporated