Water → HCID 69253307, compound

HRID 2104451Notes

Reaction equation

HRID 2104451 reaction equation
[Cl:1][C:2]1[CH:3]=[C:4]2[C:8](=[CH:9][CH:10]=1)[NH:7][C:6]([C:11]([NH:13][C@H:14]1[C@@H:19]([NH:20][C:21]([C:23]3[S:24][C:25]4[CH2:26][N:27]([CH3:32])[CH2:28][CH2:29][C:30]=4[N:31]=3)=[O:22])[CH2:18][CH2:17][C@@H:16]([C:33]([O:35]C)=[O:34])[CH2:15]1)=[O:12])=[CH:5]2.[OH-].[Li+:38].O>O1CCCC1>[Cl:1][C:2]1[CH:3]=[C:4]2[C:8](=[CH:9][CH:10]=1)[NH:7][C:6]([C:11]([NH:13][C@H:14]1[C@@H:19]([NH:20][C:21]([C:23]3[S:24][C:25]4[CH2:26][N:27]([CH3:32])[CH2:28][CH2:29][C:30]=4[N:31]=3)=[O:22])[CH2:18][CH2:17][C@@H:16]([C:33]([O-:35])=[O:34])[CH2:15]1)=[O:12])=[CH:5]2.[Li+:38]

Participants

5

Reactant 3

HCID 962WaterHCID 3939Lithium HydroxideHCID 67056702HCID 67056702, compound

Product 1

HCID 69253307HCID 69253307, compoundYield 94.8%

Reagents, catalysts & solvents 1

HCID 8028TetrahydrofuranSolvent

Procedure

The compound (1.20 g) obtained in Example 51 was dissolved in tetrahydrofuran (32 mL), and lithium hydroxide (60.8 mg) and water (4 mL) were successively added under ice cooling, followed by stirring at room temperature for 14 hours. The solvent was distilled away under reduced pressure to give the title compound (1.12 g).

Workup

  1. distillationThe solvent was distilled away under reduced pressure

Sources & evidence

ORD record
ord-1275c4ac512a4746a96dadd9a84f8136
Source dataset
uspto-grants-2009_08
Patent number
US07576135B2

Reaction notes

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