HRID21287

反应详情

EQUATION

反应方程式

HRID 21287 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

2

PROCEDURE

实验过程

In a similar manner to Step 2 of Example 1, 4-methanesulfonyloxy-5-methoxy-7-iodoisoindolinone (50.0 mg, 0.130 mmol) was dissolved in acetonitrile (3 mL), and the solution was treated with 1-(tert-butoxycarbonyl)indole-2-boronic acid (68.1 mg, 0.261 mmol), palladium acetate (2.3 mg, 0.010 mmol), tri(o-tolyl)phosphine (6.3 mg, 0.021 mmol) and triethylamine (0.181 mL, 1.30 mmol), followed by purification by flash column chromatography (hexane/ethyl acetate=7/3 to 1/1 to 3/7) to obtain 4-methanesulfonyloxy-5-methoxy-7-(1-(tert-butoxycarbonyl)indol-2-yl)isoindolinone (56.9 mg, yield 93%).

WORKUP

后处理

  1. customfollowed by purification by flash column chromatography (hexane/ethyl acetate=7/3 to 1/1 to 3/7)