HRID2137119

反应详情

EQUATION

反应方程式

HRID 2137119 的结构方程式

REACTANTS

反应物

10

结构：Cl

Hydrochloric Acid

ClH

2 次

结构：O=C([O-])O

Bicarbonate Ion

CHO3-

结构：[Na+]

Sodium ion

Na+

结构：O

Water

H2O

结构：CC#N

Acetonitrile

C2H3N

结构：CCN(CC)CC

Triethylamine

C6H15N

结构：CNOC

N-Methoxymethylamine

C2H7NO

结构：CCN=C=NCCCN(C)C

1-Ethyl-3-(3'-dimethylaminopropyl)carbodiimide

C8H17N3

结构：On1nnc2ccccc21

1-Hydroxybenzotriazole

C6H5N3O

结构：CSc1nccc(C(=O)O)n1

2-Methylsulfanylpyrimidine-4-carboxylic acid

C6H6N2O2S

PRODUCTS

生成物

1

结构：CON(C)C(=O)c1ccnc(SC)n1

N-Methoxy-N-methyl-2-(methylsulfanyl)pyrimidine-4-carboxamide

C8H11N3O2S