Hydrochloric Acid → HCID 22458196, compound

HRID 2184839Notes

Reaction equation

HRID 2184839 reaction equation
C[O:2][C:3]([C:5]1[CH:10]=[CH:9][CH:8]=[CH:7][C:6]=1[N:11]([C:28]([CH:30]1[CH2:35][CH2:34][CH2:33][CH2:32][CH2:31]1)=[O:29])[CH2:12][CH2:13][N:14]1[CH2:19][CH2:18][N:17]([C:20]2[CH:25]=[CH:24][CH:23]=[CH:22][C:21]=2[O:26][CH3:27])[CH2:16][CH2:15]1)=[O:4].[OH2:36].[OH-].[Li+].[ClH:39]>C1COCC1.O>[OH2:2].[OH2:36].[ClH:39].[CH:30]1([C:28]([N:11]([C:6]2[CH:7]=[CH:8][CH:9]=[CH:10][C:5]=2[C:3]([OH:4])=[O:2])[CH2:12][CH2:13][N:14]2[CH2:15][CH2:16][N:17]([C:20]3[CH:25]=[CH:24][CH:23]=[CH:22][C:21]=3[O:26][CH3:27])[CH2:18][CH2:19]2)=[O:29])[CH2:35][CH2:34][CH2:33][CH2:32][CH2:31]1

Participants

6

Reactant 3

HCID 313Hydrochloric AcidHCID 168937Lithium hydroxide, monohydrateHCID 22458158HCID 22458158, compound

Product 1

HCID 22458196HCID 22458196, compoundYield 84%

Reagents, catalysts & solvents 2

HCID 962WaterSolventHCID 8028TetrahydrofuranSolvent

Procedure

A solution of 0.33 g of the compound of example 18 and 0.06 g of lithium hydroxide monohydrate in 5 mL of THF and 1 mL of H2O was stirred at 70° C. for 9 h. The solution was added with 2 N aq. HCl to pH≡1 and evaporated to dryness. The residue was taken up with 10 mL of boiling Me2CO and filtered to give 0.32 g (84%) of the title compound as a white solid.

Workup

  1. customevaporated to dryness
  2. filtrationfiltered

Sources & evidence

ORD record
ord-0020c34540694152b4e15195a64a5a1a
Source dataset
uspto-grants-2002_06
Patent number
US06399614B1

Reaction notes

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