HRID2234140

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID176

Acetic Acid

C2H4O2

HCID6329

Methylamine

CH5N

HCID5003444

Sodium cyanotrihydroborate

CH3BNNa

结构：COc1cc(-c2cc(-c3cc4ccccc4n3C(=O)OC(C)(C)C)c(OC)nn2)cc(C=O)c1OCOCC[Si](C)(C)C

HCID86612060

未命名化合物

PRODUCTS

生成物

结构：CNCc1cc(-c2cc(-c3cc4ccccc4n3C(=O)OC(C)(C)C)c(OC)nn2)cc(OC)c1OCOCC[Si](C)(C)C

HCID68638496

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID887

Methanol

CH4O

溶剂HCID8028

Tetrahydrofuran

C4H8O

PROCEDURE

实验过程

175 mg of 2-{6-[3-Formyl-5-methoxy-4-(2-trimethylsilanyl-ethoxymethoxy)-phenyl]-3-methoxy-pyridazin-4-yl}-indole-1-carboxylic acid tert-butyl ester is dissolved in 5 ml of methanol and 0.16 ml of methylamine solution in THF is added. The solution is stirred for 10 min at RT then 19 mg of acetic acid and 20 mg of sodium cyanoborohydride is added. The reaction is stirred for 20 h at RT. The product is purified by preparative RP-HPLC eluting with a gradient of 0-100% acetonitrile in water (+0.01% trifluoroacetic acid). Yield 118 mg. LC-MS (ES+) 621 (M+H)+.

WORKUP

后处理

stirringThe reaction is stirred for 20 h at RT
customThe product is purified by preparative RP-HPLC
washeluting with a gradient of 0-100% acetonitrile in water (+0.01% trifluoroacetic acid)

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-17776915ea6546738f158c03ffed3104
来源数据集: uspto-grants-2010_05
DOI: 10.6084/m9.figshare.5104873.v1
专利: US07709466B2
来源说明: uspto-grants-2010_05

反应 SMILES

[C:1]([O:5][C:6]([N:8]1[C:16]2[C:11](=[CH:12][CH:13]=[CH:14][CH:15]=2)[CH:10]=[C:9]1[C:17]1[CH:22]=[C:21]([C:23]2[CH:28]=[C:27]([O:29][CH3:30])[C:26]([O:31][CH2:32][O:33][CH2:34][CH2:35][Si:36]([CH3:39])([CH3:38])[CH3:37])=[C:25]([CH:40]=O)[CH:24]=2)[N:20]=[N:19][C:18]=1[O:42][CH3:43])=[O:7])([CH3:4])([CH3:3])[CH3:2].CN.C(O)(=O)C.[C:50]([BH3-])#[N:51].[Na+]>CO.C1COCC1>[C:1]([O:5][C:6]([N:8]1[C:16]2[C:11](=[CH:12][CH:13]=[CH:14][CH:15]=2)[CH:10]=[C:9]1[C:17]1[CH:22]=[C:21]([C:23]2[CH:24]=[C:25]([CH2:40][NH:51][CH3:50])[C:26]([O:31][CH2:32][O:33][CH2:34][CH2:35][Si:36]([CH3:38])([CH3:37])[CH3:39])=[C:27]([O:29][CH3:30])[CH:28]=2)[N:20]=[N:19][C:18]=1[O:42][CH3:43])=[O:7])([CH3:4])([CH3:2])[CH3:3]