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HRID2236198

反应详情

EQUATION

反应方程式

HRID 2236198 的结构方程式

REACTANTS

反应物

3
结构：CCI
HCID6340

Ethane, iodo-

C2H5I

结构：[H-].[Na+]
HCID24758

Sodium hydride

HNa

结构：O=[N+]([O-])c1ccc(N2CC(O)C2)nc1
HCID52937264

未命名化合物

PRODUCTS

生成物

1
结构：CCOC1CN(c2ccc([N+](=O)[O-])cn2)C1
HCID59301281

2-(3-Ethoxy-azetidin-1-yl)-5-nitro-pyridine

C10H13N3O3

收率 55.5%

PROCEDURE

实验过程

1-(5-Nitro-pyridin-2-yl)-azetidin-3-ol (97.5 mg, 0.5 mmol) was treated with 60% NaH in oil (60 mg, 1.5 mmol) and ethyl iodide (400 uL, 5 mmol) as above to yield 62 mg of product following purification by flash chromatography. ES-MS calcd for C10H13N3O3 (m/e) 223.23, obsd 224.1 (M+H).