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HRID22441

反应详情

EQUATION

反应方程式

HRID 22441 的结构方程式

REACTANTS

反应物

1
结构：CCOC(=O)CC(O)(CC(=O)OCC)C(=O)OCC
HCID6506

Triethyl citrate

C12H20O7

PRODUCTS

生成物

1
结构：CCOC(=O)CC(C)=O
HCID8868

Ethyl acetoacetate

C6H10O3

AUXILIARIES

试剂、催化剂与溶剂

1
结构：CC(C)[O-].CC(C)[O-].CC(C)[O-].CC(C)[O-].[Ti+4]
催化剂HCID11026

2-Propanol, titanium(4+) salt

C12H28O4Ti

PROCEDURE

实验过程

In the same way as in Example 1, 60 g (0.21 mol) of tetraisopropyl titanate were reacted with 116.6 g (0.42 mol) of triethyl citrate. The mixture was freed of alcohol under vacuum and 154.6 g of a clear, pale yellow liquid was obtained.

WORKUP

后处理

  1. customwas obtained