Hexachloroethane → HCID 86687197, compound

HRID 2285204Notes

Reaction equation

HRID 2285204 reaction equation
ClC(Cl)(Cl)C(Cl)(Cl)Cl.[F:9][C:10]1[CH:11]=[CH:12][C:13]([NH:16][NH:17][C:18]([C@@H:20]2[CH2:25][CH2:24][CH2:23][CH2:22][N:21]2[CH3:26])=O)=[N:14][CH:15]=1.C(N(CC)CC)C.C1(P(C2C=CC=CC=2)C2C=CC=CC=2)C=CC=CC=1>C1COCC1.CO>[F:9][C:10]1[CH:11]=[CH:12][C:13]2[N:14]([C:18]([C@@H:20]3[CH2:25][CH2:24][CH2:23][CH2:22][N:21]3[CH3:26])=[N:17][N:16]=2)[CH:15]=1

Participants

7

Reactant 4

HCID 6214HexachloroethaneHCID 8471TriethylamineHCID 11776TriphenylphosphineHCID 86687196HCID 86687196, compound

Product 1

HCID 86687197HCID 86687197, compoundYield 42%

Reagents, catalysts & solvents 2

HCID 887MethanolSolventHCID 8028TetrahydrofuranSolvent

Procedure

Hexachloroethane (505 mg, 2.14 mmol) was added portionwise over 5 min at RT to a stirred mixture of Intermediate 120a (270 mg, 1.07 mmol), triethylamine (595 μL, 4.28 mmol) and triphenylphosphine (560 mg, 2.14 mmol) in THF (10 mL). The reaction mixture was stirred for 1.5 h and then diluted with methanol and loaded onto an SCX cartridge. The cartridge was washed with MeOH and the product eluted with 2M NH3 in MeOH and concentrated in vacuo. The resultant residue was purified by FCC on silica, using a gradient of 0-8% [2M NH3 in MeOH] in EtOAc to give the title compound (105 mg, 42%). 1H NMR (400 MHz, CDCl3): 1.34-1.51 (1H, m), 1.62-1.92 (5H, m), 2.00 (3H, s), 2.20 (1H, td, J=11.4, 3.7 Hz), 3.06 (1H, m), 3.87 (1H, dd, J=10.9, 3.3 Hz), 7.18 (1H, ddd, J=9.8, 7.6, 2.3 Hz), 7.71 (1H, ddd, J=9.9, 5.0, 0.7 Hz), 8.75-7.79 (1H, m).

Workup

  1. washThe cartridge was washed with MeOH
  2. washthe product eluted with 2M NH3 in MeOH
  3. concentrationconcentrated in vacuo
  4. customThe resultant residue was purified by FCC on silica

Sources & evidence

ORD record
ord-bf8e385d922e4224a327eee03fcaa1e5
Source dataset
uspto-grants-2015_09
Patent number
US09145413B2

Reaction notes

Loading…