Isopropanol → Isopropyl 2-pyridylacetate
Reaction equation
Cl.[N:2]1[CH:7]=[CH:6][CH:5]=[CH:4][C:3]=1[CH2:8][C:9]([OH:11])=[O:10].C(=O)(O)[O-].[Na+].[CH3:17][CH:18](O)[CH3:19]>Cl>[N:2]1[CH:7]=[CH:6][CH:5]=[CH:4][C:3]=1[CH2:8][C:9]([O:11][CH:18]([CH3:19])[CH3:17])=[O:10]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
In a solution of 355 mg of 2-pyridylacetic acid hydrochloride in 5 ml of 2-propanol, hydrogen chloride was saturated at 0° C., and the solution was stirred for 10 hours at room temperature. Sodium bicarbonate was added to the reaction mixture to make alkaline, and the solution was extracted with 50 ml of diethyl ether. The ethereal layer was washed successively with water and a suturated aqueous sodium chloride solution, and dried over anhydrous sodium sulfate, and the solvent was evaporated under reduced pressure to give 305 mg of isopropyl 2-pyridylacetate as an oil.
Workup
- customwas saturated at 0° C.
- extractionthe solution was extracted with 50 ml of diethyl ether
- washThe ethereal layer was washed successively with water
- dry with materiala suturated aqueous sodium chloride solution, and dried over anhydrous sodium sulfate
- customthe solvent was evaporated under reduced pressure
Sources & evidence
- ORD record
- ord-2d6bf61e39b146b58352126b68dd1358
- Source dataset
- uspto-grants-1989_10
- Patent number
- US04877795
Reaction notes
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