1-Pentyn-3-ol → rac-(Z)-1,3-Dihydro-5-fluoro-4-(3-hydroxy-1-pentynyl)-3-[(1H-pyrrol-2-yl)methylene]-2H-indol-2-one

HRID 380861Notes

Reaction equation

HRID 380861 reaction equation
[CH:1]#[C:2][CH:3]([OH:6])[CH2:4][CH3:5].[F:7][C:8]1[C:9](I)=[C:10]2[C:14](=[CH:15][CH:16]=1)[NH:13][C:12](=[O:17])/[C:11]/2=[CH:18]\[C:19]1[NH:20][CH:21]=[CH:22][CH:23]=1>C1C=CC([P]([Pd]([P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)([P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)[P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)=CC=1.[Cu]I.CN(C=O)C.CCN(CC)CC>[F:7][C:8]1[C:9]([C:1]#[C:2][CH:3]([OH:6])[CH2:4][CH3:5])=[C:10]2[C:14](=[CH:15][CH:16]=1)[NH:13][C:12](=[O:17])/[C:11]/2=[CH:18]\[C:19]1[NH:20][CH:21]=[CH:22][CH:23]=1

Participants

7

Procedure

Using Method C above, 1-pentyn-3-ol (58.9 mg, 0.7 mmol) (Aldrich) was coupled with (Z)-1,3-dihydro-5-fluoro-4-iodo-3-[(1H-pyrrol-2-yl)methylene]-2H-indol-2-one (100 mg, 0.28 mmol) (Starting Material 5, supra) using (Ph3P)4Pd (32 mg) and CuI (5.3 mg) as catalyst in DMF (5 mL) and Et3N (5 mL) as solvent at 85° C. for 10 h to yield rac-(Z)-1,3-Dihydro-5-fluoro-4-(3-hydroxy-1-pentynyl)-3-[(1H-pyrrol-2-yl)methylene]-2H-indol-2-one. (Yield 64 mg, 70%).

Sources & evidence

ORD record
ord-f048178df18144d4bd734efe3c90acf2
Source dataset
uspto-grants-2001_10
Patent number
US06303793B1

Reaction notes

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