HRID411068

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID674

Dimethylamine

C2H7N

HCID81531

Diisopropylethylamine

C8H19N

结构：CN(C)C(On1nnc2ccccc21)=[N+](C)C.F[P-](F)(F)(F)(F)F

HCID2733084

Methanaminium, N-[(1H-benzotriazol-1-yloxy)(dimethylamino)methylene]-N-methyl-, hexafluorophosphate(1-) (1:1)

C11H16F6N5OP

结构：Cn1c(Nc2nc3ccc(C(F)(F)F)cc3s2)nc2cc(C(=O)NCC(=O)N[C@@H](CCCCNC(=O)OC(C)(C)C)C(=O)O)ccc21

HCID86656981

未命名化合物

PRODUCTS

生成物

结构：CN(C)C(=O)[C@H](CCCCNC(=O)OC(C)(C)C)NC(=O)CNC(=O)c1ccc2c(c1)nc(Nc1nc3ccc(C(F)(F)F)cc3s1)n2C

HCID86656982

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID6228

N,N-Dimethylformamide

C3H7NO

溶剂HCID8028

Tetrahydrofuran

C4H8O

PROCEDURE

实验过程

[(S)-5-Dimethylcarbamoyl-5-(2-{[1-methyl-2-(6-trifluoromethyl-benzothiazol-2-ylamino)-1H-benzoimidazole-5-carbonyl]-amino}-acetylamino)-pentyl]-carbamic acid tert-butyl ester (200 mg) was prepared by following General Procedure F starting from (S)-6-tert-butoxycarbonylamino-2-(2-{[1-methyl-2-(6-trifluoromethyl-benzothiazol-2-ylamino)-1H-benzoimidazole-5-carbonyl]-amino}-acetylamino)-hexanoic acid (260 mg), 2 M dimethylamine in THF (1 mL), HBTU (400 mg), and DIEA (400 uL) in DMF (2 mL).

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-0c5363599f534d2f88683412cd5276b1
来源数据集: uspto-grants-2014_06
DOI: 10.6084/m9.figshare.5104873.v1
专利: US08759535B2
来源说明: uspto-grants-2014_06

反应 SMILES

[C:1]([O:5][C:6]([NH:8][CH2:9][CH2:10][CH2:11][CH2:12][C@H:13]([NH:17][C:18](=[O:47])[CH2:19][NH:20][C:21]([C:23]1[CH:46]=[CH:45][C:26]2[N:27]([CH3:44])[C:28]([NH:30][C:31]3[S:32][C:33]4[CH:39]=[C:38]([C:40]([F:43])([F:42])[F:41])[CH:37]=[CH:36][C:34]=4[N:35]=3)=[N:29][C:25]=2[CH:24]=1)=[O:22])[C:14](O)=[O:15])=[O:7])([CH3:4])([CH3:3])[CH3:2].[CH3:48][NH:49][CH3:50].CN(C(ON1N=NC2C=CC=CC1=2)=[N+](C)C)C.F[P-](F)(F)(F)(F)F.CCN(C(C)C)C(C)C>C1COCC1.CN(C=O)C>[C:1]([O:5][C:6](=[O:7])[NH:8][CH2:9][CH2:10][CH2:11][CH2:12][C@@H:13]([C:14](=[O:15])[N:49]([CH3:50])[CH3:48])[NH:17][C:18](=[O:47])[CH2:19][NH:20][C:21]([C:23]1[CH:46]=[CH:45][C:26]2[N:27]([CH3:44])[C:28]([NH:30][C:31]3[S:32][C:33]4[CH:39]=[C:38]([C:40]([F:43])([F:41])[F:42])[CH:37]=[CH:36][C:34]=4[N:35]=3)=[N:29][C:25]=2[CH:24]=1)=[O:22])([CH3:4])([CH3:3])[CH3:2]