Phenylacetylene → HCID 9819310, compound

HRID 428650Notes

Reaction equation

HRID 428650 reaction equation
[C:1]1([C:7]#[CH:8])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.Br[C:10]1[CH:18]=[CH:17][CH:16]=[C:15]2[C:11]=1/[C:12](=[CH:20]/[C:21]1[NH:22][CH:23]=[CH:24][C:25]=1[O:26][CH3:27])/[C:13](=[O:19])[NH:14]2>[Cu]I.CN(C=O)C.CCN(CC)CC>[C:1]1([C:7]#[C:8][C:10]2[CH:18]=[CH:17][CH:16]=[C:15]3[C:11]=2/[C:12](=[CH:20]/[C:21]2[NH:22][CH:23]=[CH:24][C:25]=2[O:26][CH3:27])/[C:13](=[O:19])[NH:14]3)[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1

Participants

6

Reactant 2

HCID 10821PhenylacetyleneHCID 18359254(Z)-4-bromo-1,3-dihydro-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2H-indol-2-one2×

Product 1

HCID 9819310HCID 9819310, compound

Reagents, catalysts & solvents 3

HCID 24350Copper(1+) iodide; Copper(I) iodide; Cuprous iodide; Cuprous iodide (CuI)CatalystHCID 6228DimethylformamideSolventHCID 8471TriethylamineSolvent

Procedure

Using general Method D above, phenyl acetylene (32 mg, 0.31 mmol) (Aldrich) was coupled with (Z)-4-bromo-1,3-dihydro-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2H-indol-2-one (50 mg, 0.16 mmol) (Starting Material 1) using DPPFPdCl2 (6.5 mg) (Aldrich) and CuI (1.5 mg) (Aldrich) as catalyst in DMF (2 mL) and Et3N (3 mL) as solvent at 85° C. for 18 h, to yield (Z)-1,3-dihydro-4-(phenylethynyl)-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2H-indol-2-one. (Yield 20 mg, 37%)

Sources & evidence

ORD record
ord-fab85563ea1e470ba5dc70f3bcef501b
Source dataset
uspto-grants-2001_11
Patent number
US06313310B1

Reaction notes

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