Hydrogen Peroxide → Catechol

HRID 434424Notes

Reaction equation

HRID 434424 reaction equation
[C:1]1([OH:7])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.[OH:8]O>[Ti].O>[C:1]1([C:6](=[CH:5][CH:4]=[CH:3][CH:2]=1)[OH:8])[OH:7].[C:1]1([CH:6]=[CH:5][C:4]([OH:8])=[CH:3][CH:2]=1)[OH:7]

Participants

6

Reactant 2

HCID 784Hydrogen PeroxideHCID 996Phenol

Product 2

HCID 289CatecholHCID 785Hydroquinone

Reagents, catalysts & solvents 2

HCID 23963TitaniumCatalystHCID 962WaterSolvent

Procedure

A 10-liter reactor as for the previous Example is charged with 4,255.8 g of phenol, 813 g of water and 42 g of titanium silicalite. As the system has reached its thermal equilibrium, there are added 675.2 g of 60% H2O2. After three hours of reaction there are obtained 250 g of pyrocatechol, 318 g of hydroquinone and 157 g of tarry by-products.

Workup

  1. customAfter three hours of reaction

Sources & evidence

ORD record
ord-fff43175f890498f9978d5a0eac06198
Source dataset
uspto-grants-1983_08
Patent number
US04396783

Reaction notes

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