Methyl iodide → 5-Methylthiopyrano[3,2-b]indol-4(5H)-one
Reaction equation
[H-].[Na+].[S:3]1[C:15]2[C:14]3[CH:13]=[CH:12][CH:11]=[CH:10][C:9]=3[NH:8][C:7]=2[C:6](=[O:16])[CH:5]=[CH:4]1.[CH3:17]I>CCCCCC.CN(C)C=O>[CH3:17][N:8]1[C:9]2[CH:10]=[CH:11][CH:12]=[CH:13][C:14]=2[C:15]2[S:3][CH:4]=[CH:5][C:6](=[O:16])[C:7]1=2Participants
6
Reactant 3
Product 1
Reagents, catalysts & solvents 2
Procedure
Sodium hydride (2.3 g of 50% suspension in mineral oil, 0.05 mole) is washed with hexane and suspended in 25 ml of dimethylformamide (DMF). Thiopyrano [3,2-b]indol-4(5H)-one, 10.0 g (0.05 mole) in 130 ml of DMF is added and the mixture stirred for 3 hours. Methyl iodide (14.2 g, 0.1 mole) is added and the mixture stirred for 3 hours and then poured over ice. The white precipitate is filtered, dried and recrystallized from hexane to give 9.3 g of product, mp 113°-114° C.
Workup
- stirringthe mixture stirred for 3 hours
- additionpoured over ice
- filtrationThe white precipitate is filtered
- customdried
- customrecrystallized from hexane
Sources & evidence
- ORD record
- ord-630c046baf5e43b3a726f81d98b399ca
- Source dataset
- uspto-grants-1977_06
- Patent number
- US04032537
Reaction notes
Loading…