Water → Phenacyltetrahydrothiophenium bromide
Reaction equation
[CH2:1]([Br:10])[C:2]([C:4]1[CH:9]=[CH:8][CH:7]=[CH:6][CH:5]=1)=[O:3].[S:11]1[CH2:15][CH2:14][CH2:13][CH2:12]1.O.C(OCC)C>[N+](C)([O-])=O>[Br-:10].[CH2:1]([S+:11]1[CH2:15][CH2:14][CH2:13][CH2:12]1)[C:2]([C:4]1[CH:9]=[CH:8][CH:7]=[CH:6][CH:5]=1)=[O:3]Participants
6
Reactant 4
Product 1
Reagents, catalysts & solvents 1
Procedure
Phenacyl bromide, 88.2 g (0.44 mole) and tetrahydrothiophene, 39.1 g (0.44 mole) were dissolved in 220 g of nitromethane, which was stirred for 4 hours at room temperature. The reaction solution was combined with 800 g of water and 400 g of diethyl ether. The aqueous layer separated was taken out, which was an aqueous solution of the target compound, phenacyltetrahydrothiophenium bromide.
Workup
- customThe aqueous layer separated
Sources & evidence
- ORD record
- ord-357c4cbcd5cd4528851205250f3de92c
- Source dataset
- uspto-grants-2011_11
- Patent number
- US08048610B2
Reaction notes
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