Hydrogen Peroxide → Catechol
Reaction equation
[C:1]1([OH:7])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.C(C(C)=[O:13])C(C)C.OO>>[C:1]1([C:6](=[CH:5][CH:4]=[CH:3][CH:2]=1)[OH:13])[OH:7].[C:1]1([CH:6]=[CH:5][C:4]([OH:13])=[CH:3][CH:2]=1)[OH:7]Participants
5
Conditions
- Temperature
- 100 °C
Procedure
In a 300 ml four-necked flask equipped with a stirrer, a condenser, and a thermometer were charged 65.8 g (0.7 mol) of phenol, 3.5 g (0.035 mol) of methyl isobutyl ketone, and 50 mg of each of the compounds shown in Table 1 below as a catalyst. The mixture was heated to 100° C., and 1.98 g (0.035 mol) of 60 wt % aqueous hydrogen peroxide was added thereto, followed by stirring for 30 minutes. The resulting reaction mixture was analyzed by gas chromatography to obtain yields of catechol and hydroquinone. The results obtained are shown in Table 1.
Workup
- customIn a 300 ml four-necked flask equipped with a stirrer, a condenser
- customThe resulting reaction mixture
- customto obtain
Sources & evidence
- ORD record
- ord-ff522065591d4b25b776461305f81ad5
- Source dataset
- uspto-grants-1992_08
- Patent number
- US05138104
Reaction notes
Loading…