Hydrochloric Acid → HCID 67127105, compound
Reaction equation
[NH:1]1[C:5]2=[N:6][CH:7]=[C:8]([O:10][C:11]3[CH:20]=[C:19]([N:21]4[CH2:26][CH2:25][N:24]([CH2:27][C:28]5[CH2:29][O:30][C:31]([CH3:42])([CH3:41])[CH2:32][C:33]=5[C:34]5[CH:39]=[CH:38][C:37]([Cl:40])=[CH:36][CH:35]=5)[CH2:23][CH2:22]4)[CH:18]=[CH:17][C:12]=3[C:13]([O:15]C)=[O:14])[CH:9]=[C:4]2[CH:3]=[CH:2]1.O[Li].O.Cl>O1CCCC1.CO.O.C(OCC)(=O)C>[NH:1]1[C:5]2=[N:6][CH:7]=[C:8]([O:10][C:11]3[CH:20]=[C:19]([N:21]4[CH2:22][CH2:23][N:24]([CH2:27][C:28]5[CH2:29][O:30][C:31]([CH3:42])([CH3:41])[CH2:32][C:33]=5[C:34]5[CH:35]=[CH:36][C:37]([Cl:40])=[CH:38][CH:39]=5)[CH2:25][CH2:26]4)[CH:18]=[CH:17][C:12]=3[C:13]([OH:15])=[O:14])[CH:9]=[C:4]2[CH:3]=[CH:2]1Participants
8
Procedure
To a solution of EXAMPLE 15G (254 mg) in tetrahydrofuran (4 mL), methanol (2 mL) and water (2 mL) was added LiOH H2O (126 mg). The mixture was stirred overnight. The mixture was then neutralized with 5% HCl and diluted with ethyl acetate (200 mL). After washing with brine, it was dried over Na2SO4. Filtration and evaporation of solvent gave the product.
Workup
- washAfter washing with brine, it
- dry with materialwas dried over Na2SO4
- filtrationFiltration and evaporation of solvent
- customgave the product
Sources & evidence
- ORD record
- ord-a27001d10423476c8e8aaaa24516998d
- Source dataset
- uspto-grants-2013_10
- Patent number
- US08546399B2
Reaction notes
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