Potassium Iodide → Hydrochloric Acid

HRID 1382406Notes

Reaction equation

HRID 1382406 reaction equation
[N:1]1[CH:6]=[CH:5][CH:4]=[CH:3][C:2]=1[N:7]1[CH2:12][CH2:11][NH:10][CH2:9][CH2:8]1.[Cl:13][CH2:14][CH2:15][CH:16]([OH:26])[CH2:17][O:18][C:19]1[CH:24]=[CH:23][C:22]([Cl:25])=[CH:21][CH:20]=1.C(=O)([O-])[O-].[Na+].[Na+].[I-].[K+]>CC(O)C.C(O)CCC>[ClH:13].[ClH:13].[Cl:25][C:22]1[CH:23]=[CH:24][C:19]([O:18][CH2:17][CH:16]([OH:26])[CH2:15][CH2:14][N:10]2[CH2:9][CH2:8][N:7]([C:2]3[CH:3]=[CH:4][CH:5]=[CH:6][N:1]=3)[CH2:12][CH2:11]2)=[CH:20][CH:21]=1.[ClH:13]

Participants

8

Reactant 4

HCID 4875Potassium IodideHCID 10340Sodium CarbonateHCID 944591-(2-Pyridyl)piperazineHCID 131203494-Chloro-1-(4-chlorophenoxy)-2-butanol

Product 2

HCID 313Hydrochloric AcidHCID 14422863HCID 14422863, compound

Reagents, catalysts & solvents 2

HCID 2631-ButanolSolventHCID 3776IsopropanolSolvent

Procedure

This compound was prepared according to the procedure of Example 97. A mixture of 5.0 g (0.03 mole) of 1-(2-pyridyl)piperazine, 7.0 g (0.03 mole) of 4-chloro-1-(4-chlorophenoxy)-2-butanol, 16.0 g (0.15 mole) of anhydrous sodium carbonate and 0.3 g (0.002 mole) of potassium iodide in a total volume of 200 ml of 1-butanol gave a golden oil as residue. The hydrochloride was formed in 2-propanol saturated with hydrogen chloride and the collected solid was recrystallized from aqueous 2-propanol to give 8.1 g (62%) of white solid, m.p. >245° C.

Workup

  1. customThis compound was prepared
  2. customgave a golden oil as residue

Sources & evidence

ORD record
ord-2a8656d2d8d14f1c925f2d49b974c5d8
Source dataset
uspto-grants-1989_02
Patent number
US04806555

Reaction notes

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