Potassium Iodide → Hydrochloric Acid

HRID 1382408Notes

Reaction equation

HRID 1382408 reaction equation
[Cl:1][CH2:2][CH2:3][CH:4]([OH:14])[CH2:5][O:6][C:7]1[CH:12]=[CH:11][C:10]([F:13])=[CH:9][CH:8]=1.[F:15][C:16]1[CH:21]=[CH:20][C:19]([N:22]2[CH2:27][CH2:26][NH:25][CH2:24][CH2:23]2)=[CH:18][CH:17]=1.C(=O)([O-])[O-].[Na+].[Na+].[I-].[K+]>CC(O)C.C(O)CCC>[ClH:1].[F:13][C:10]1[CH:11]=[CH:12][C:7]([O:6][CH2:5][CH:4]([OH:14])[CH2:3][CH2:2][N:25]2[CH2:24][CH2:23][N:22]([C:19]3[CH:18]=[CH:17][C:16]([F:15])=[CH:21][CH:20]=3)[CH2:27][CH2:26]2)=[CH:8][CH:9]=1.[ClH:1]

Participants

8

Reactant 4

HCID 4875Potassium IodideHCID 10340Sodium CarbonateHCID 752601-(4-Fluorophenyl)piperazineHCID 14422830HCID 14422830, compound

Product 2

HCID 313Hydrochloric AcidHCID 14422882HCID 14422882, compound

Reagents, catalysts & solvents 2

HCID 2631-ButanolSolventHCID 3776IsopropanolSolvent

Procedure

This compound was prepared according to the procedure of Example 97. A mixture of 6.5 g (0.03 mole) of 4-chloro-1-(4-fluorophenoxy)-2-butanol, 5.4 g (0.03 mole) of 1-(4-fluorophenyl)piperazine, 16.0 g (0.15 mole) of anhydrous sodium carbonate and 0.3 g (0.002 mole) of potassium iodide in a total volume of 200 ml of 1-butanol gave a golden oil as residue. The hydrochloric acid salt was formed in 2-propanol saturated with hydrogen chloride, and the collected solid was recrystallized from methanol-water-ethyl ether to give 6.7 g (56%) of white solid, m.p. 161°-165° C.

Workup

  1. customThis compound was prepared
  2. customgave a golden oil as residue

Sources & evidence

ORD record
ord-d89dfb1c2adc40d79d98c25c910dba19
Source dataset
uspto-grants-1989_02
Patent number
US04806555

Reaction notes

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