Hydrochloric Acid → HCID 67227918, compound

HRID 1520598Notes

Reaction equation

HRID 1520598 reaction equation
[NH:1]1[C:9]2[C:4](=[C:5]([O:10][C:11]3[CH:21]=[C:20]([N:22]4[CH2:27][CH2:26][N:25]([CH2:28][C:29]5[CH2:33][CH2:32][CH2:31][C:30]=5[C:34]5[CH:39]=[CH:38][C:37]([Cl:40])=[CH:36][CH:35]=5)[CH2:24][CH2:23]4)[CH:19]=[CH:18][C:12]=3[C:13]([O:15]CC)=[O:14])[CH:6]=[CH:7][CH:8]=2)[CH:3]=[CH:2]1.O[Li].O.Cl>O1CCCC1.CO.O.C(OCC)(=O)C>[NH:1]1[C:9]2[C:4](=[C:5]([O:10][C:11]3[CH:21]=[C:20]([N:22]4[CH2:23][CH2:24][N:25]([CH2:28][C:29]5[CH2:33][CH2:32][CH2:31][C:30]=5[C:34]5[CH:35]=[CH:36][C:37]([Cl:40])=[CH:38][CH:39]=5)[CH2:26][CH2:27]4)[CH:19]=[CH:18][C:12]=3[C:13]([OH:15])=[O:14])[CH:6]=[CH:7][CH:8]=2)[CH:3]=[CH:2]1

Participants

8

Reactant 3

HCID 313Hydrochloric AcidHCID 168937Lithium hydroxide, monohydrateHCID 67227090HCID 67227090, compound

Product 1

HCID 67227918HCID 67227918, compound

Reagents, catalysts & solvents 4

HCID 887MethanolSolventHCID 962WaterSolventHCID 8028TetrahydrofuranSolventHCID 8857Ethyl AcetateSolvent

Procedure

To a solution of EXAMPLE 143E (254 mg) in tetrahydrofuran (4 ml), methanol (2 ml) and water (2 ml) was added LiOH—H2O (126 mg). The mixture was stirred overnight. The mixture was then neutralized with 5% HCl and diluted with ethyl acetate (200 ml). After washing with brine, it was dried over Na2SO4. Evaporation of solvent gave the product.

Workup

  1. washAfter washing with brine, it
  2. dry with materialwas dried over Na2SO4
  3. customEvaporation of solvent
  4. customgave the product

Sources & evidence

ORD record
ord-be5204b084cf4a808fa945fd0ebcf87c
Source dataset
uspto-grants-2015_07
Patent number
US09073855B2

Reaction notes

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