Hydrogen Peroxide → Catechol

HRID 1678931Notes

Reaction equation

HRID 1678931 reaction equation
[C:1]1([OH:7])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.OO.S([O-])([O-])(=O)=[O:11].[Al+3].S([O-])([O-])(=O)=[O:17].S([O-])([O-])(=O)=O.[Al+3]>>[C:1]1([C:6](=[CH:5][CH:4]=[CH:3][CH:2]=1)[OH:11])[OH:7].[C:1]1([CH:6]=[CH:5][C:4]([OH:17])=[CH:3][CH:2]=1)[OH:7]

Participants

5

Reactant 3

HCID 784Hydrogen PeroxideHCID 996PhenolHCID 24850Aluminum Sulfate

Product 2

HCID 289CatecholHCID 785Hydroquinone

Procedure

10 g. (106 m. moles) of phenol, 8.20 m. moles of the ketone indicated in Table 3, 0.300 g. (5.29 m. moles) of 60 percent hydrogen peroxide, 0.070 g. of aluminum sulfate (Al2 (SO4)3.18H2O) (miligramion 0.315 of SO4 --) were mixed together and the resulting mixture was reacted at 100° C. for 30 minutes in the same manner as in Example 1. Yields of catechol and hydroquinone are shown in Table 3.

Workup

  1. customthe resulting mixture was reacted at 100° C. for 30 minutes in the same manner as in Example 1

Sources & evidence

ORD record
ord-50e9a49371eb4260a2e770a0535734f8
Source dataset
uspto-grants-1978_03
Patent number
US04078006

Reaction notes

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