反应详情
EQUATION
反应方程式
REACTANTS
反应物
PRODUCTS
生成物
AUXILIARIES
试剂、催化剂与溶剂
PROCEDURE
实验过程
5-[2-Amino-6-(2-aminoethylsulfanyl)pyrimidin-4-yl]-2,4-dimethylbenzoic acid tert-butyl ester (1.9 g, 5.10 mmol) obtained in Step 1 above, DL-2,4-bis((tert-butoxycarbonyl)amino)butyric acid (which can be prepared from commercially available DL-2,4-diaminobutyric acid dihydrochloride by the method described in Journal of Inorganic Biochemistry (2004) 98(11): 1933-1946) (4.9 g, 15.3 mmol), and 1-hydroxybenzotriazole (2.1 g, 15.3 mmol) were dissolved in N,N-dimethylformamide (40 ml). 1-Ethyl-3-(3′-dimethylaminopropyl)carbodiimide hydrochloride (2.9 g, 15.3 mmol) and diisopropylethylamine (3.6 ml, 20.4 mmol) were added to the solution, and stirred overnight at room temperature. The reaction solution was diluted with ethyl acetate (400 ml), and then sequentially washed with a saturated aqueous sodium bicarbonate solution (300 ml), water (300 ml, three times), and a saturated aqueous sodium chloride solution (300 ml). After the organic layer was dried over anhydrous sodium sulfate (50 g), the inorganic salt was filtered and washed with ethyl acetate. The filtrate and washing solution were combined together, and concentrated under reduced pressure. The resulting residue was purified by silica gel column chromatography (developing solvent: dichloromethane:methanol=40:1) to yield 5-{2-amino-6-[2-(2,4-bis-tert-butoxycarbonylaminobutyrylamino)ethylsulfanyl]pyrimidin-4-yl}-2,4-dimethylbenzoic acid tert-butyl ester (3.2 g) as a white solid material.
WORKUP
后处理
- washsequentially washed with a saturated aqueous sodium bicarbonate solution (300 ml), water (300 ml, three times)
- dry with materialAfter the organic layer was dried over anhydrous sodium sulfate (50 g)
- filtrationthe inorganic salt was filtered
- washwashed with ethyl acetate
- washThe filtrate and washing solution
- concentrationconcentrated under reduced pressure
- customThe resulting residue was purified by silica gel column chromatography (developing solvent: dichloromethane:methanol=40:1)