Hydrochloric Acid → Anthranilic acid, N-(2-methoxyphenyl)-
Reaction equation
Cl[C:2]1[CH:10]=[CH:9][CH:8]=[CH:7][C:3]=1[C:4]([OH:6])=[O:5].[CH3:11][O:12][C:13]1[CH:19]=[CH:18][CH:17]=[CH:16][C:14]=1[NH2:15].C(=O)([O-])[O-].[K+].[K+].Cl>CN(C)C=O>[CH3:11][O:12][C:13]1[CH:19]=[CH:18][CH:17]=[CH:16][C:14]=1[NH:15][C:2]1[CH:10]=[CH:9][CH:8]=[CH:7][C:3]=1[C:4]([OH:6])=[O:5]Participants
6
Reactant 4
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 120 °C
Procedure
A mixture of 40 g (0.25 mole) of 2-chlorobenzoic acid, 21 ml (0.26 mole) of 2-methoxyaniline, 3.84 g cupric acetate, 35.4 g of potassium carbonate and 155 ml of dimethylformamide was heated at 120° C. for 12 hours. The reaction mixture was poured into ice-water, acidified with concentrated hydrochloric acid to pH 2, and stirred for one hour. The solid product was collected by filtration, air dried and recrystallized from toluene to give 28.61 g of 2-(2-methoxyphenylamino)benzoic acid.
Workup
- filtrationThe solid product was collected by filtration, air
- customdried
- customrecrystallized from toluene
Sources & evidence
- ORD record
- ord-306546e7cdf84c17a109594c8334b072
- Source dataset
- uspto-grants-1985_04
- Patent number
- US04510139
Reaction notes
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