Methylparaben → Methyl 4-(3-chloropropoxy)benzoate
Reaction equation
[OH:1][C:2]1[CH:11]=[CH:10][C:5]([C:6]([O:8][CH3:9])=[O:7])=[CH:4][CH:3]=1.C(=O)([O-])[O-].[K+].[K+].Br[CH2:19][CH2:20][CH2:21][Cl:22]>CN(C)C=O>[Cl:22][CH2:21][CH2:20][CH2:19][O:1][C:2]1[CH:3]=[CH:4][C:5]([C:6]([O:8][CH3:9])=[O:7])=[CH:10][CH:11]=1Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
Following the procedure described in example 1§E, but starting from methyl 4-hydroxybenzoate (15.2 g), potassium carbonate (65 g) and 1-bromo-3-chloropropane (50 mL) in N,N-dimethylformamide (100 mL) affords 22.5 g of methyl 4-(3-chloropropoxy)benzoate as an oil.
Sources & evidence
- ORD record
- ord-9554c09c5cc5439091f9820f0057af3c
- Source dataset
- uspto-grants-2011_12
- Patent number
- US08076329B2
Reaction notes
Loading…