HRID2136512

反应详情

EQUATION

反应方程式

HRID 2136512 的结构方程式

REACTANTS

反应物

9

结构：[NH4+]

Ammonia ion (NH4+)

H4N+

结构：[Cl-]

Chloride

Cl-

结构：Cl

Hydrochloric Acid

ClH

结构：O

Water

H2O

结构：CN(C)C=O

N,N-Dimethylformamide

C3H7NO

结构：CCN=C=NCCCN(C)C

1-Ethyl-3-(3'-dimethylaminopropyl)carbodiimide

C8H17N3

结构：CCN(C(C)C)C(C)C

Diisopropylethylamine

C8H19N

结构：On1nnc2cccnc21

3H-1,2,3-Triazolo[4,5-b]pyridine, 3-hydroxy-

C5H4N4O

结构：O=C(O)c1cc(Cl)ccc1-n1cnnn1

5-Chloro-2-(1H-tetrazol-1-yl)benzoic acid

C8H5ClN4O2

PRODUCTS

生成物

1

结构：NC(=O)c1cc(Cl)ccc1-n1cnnn1

5-Chloro-2-(1H-tetrazol-1-yl)benzamide

C8H6ClN5O